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# HOW TO CALCULATE THE QUANTITY OF BRICK, CEMENT & SAND IN 9 INCH BRICK WALL

Quantity of Bricks:-

Assuming:-

• Brick size = 9”x4.5”x3”
•Thickness of wall = 9”
•Thickness of mortar = 0.39
•Brick size with mortar= (9+0.39)x(4.5+0.39)x(3+0.39) = 9.39”x4.89”x3.39” •

No. of bricks = Volume of Brickwork/ Volume of 1 Brick with mortar

Volume of 1 Brick = (9/12)x(4.5/12)x(3/12)= 0.75’x0.375’x0.25’ = 0.070 CFT

Volume of 1 Brick with mortar = 0.783’x0.408’x0.283’=0.090 CFT.

Volume of Brickwork = 10’ x 6’ x 0.75’ = 45 Cubic Foot (CFT)

No. of bricks = Volume of Brickwork/ Volume of 1 Brick with Mortar

∴ No. of bricks = 45 CFT/ 0.090 CFT

= 500 No’s

Brick wastage–> 5 to 10 %

Consider 10% brick wastage,

∴ No. of bricks= 500  + (500 x 0.1)

= 550 No’s

Quantity of cement:-

Quantity of mortar = Quantity of brickwork – Volume of Bricks

Volume of bricks =0.070 CFT x 500 No’s = 35 CFT

Quantity of mortar = 45 – 35

= 10 CFT

Mix Ratio –> 1:5

Dry volume of mortar = Wet volume x (1+0.33) (33% of volume)

Dry Volume of mortar= 10 x 1.33 = 13.3 CFT

Consider 5% wastage of mortar.

Dry volume of mortar = 13.3 + (13.3 x 0.05) = 13.3+0.665 = 13.965 ≊ 14 CFT

Quantity of Cement = {(Dry Volume of mortar x Cement ratio) / (Sum of the ratio)}

∴Quantity of cement = (14 x 1) /(1+5)=2.333 CFT

Density of Cement = 1440 kg/m³

1 m³=35.3147 Cubic Feet (CFT)

∴ Quantity of Cement = 2.333/35.3147 = 0.066 m³

∴ Weight of Cement = 1440 x 0.066 = 95.04 Kg

1 bag of cement contains 50 kg of cement

∴ Number of bags = 95.04 Kg / 50 kg = 1.90 No’s (Say 2 No of bags)

Quantity of Sand:-

Cement : Sand :: 1:5

Quantity of Sand = Quantity of Cement x 5

∴ Quantity of Sand = 2.333 x 5= 11.665 CFT

1 m³=35.3147 Cubic Feet (CFT)

∴ Quantity of sand = 11.665/35.3147 = 0.330 m³

Density of sand = 1600 kg/m³

∴ Weight of the sand= 0.330 x 1600= 528 kg (0.528 tonnes)

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